Question

A die is thrown once point find the probability
of getting a number lying between
2 and 6​

Answer 1

Answer:

required probability=1/2

Step-by-step explanation:

sample space={1,2,3,4,5,6}   N{S}=6

let 'E' be an event getting a number between 2 and 6

so E={3,4,5}

N{E}=3

probability=N{E}/N{S}

                =3/6=1/2

So the required probability is 1/2

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Answer 2

Answer:

Probability = 0.5

Step-by-step explanation:

Total posible outcome = { 1, 2 , 3, 4, 5, 6}

Number of possible outcomes = 6

Favourable outcome = { 3, 4, 5 } ( That is no. lying btw 2 and 6 )

Number of favourable outcomes = 3

P ( F) = Number of favourable outcomes / Number of possible outcomes

P ( F) = 3 / 6

= 1/2

Probability = 0.5