A die is thrown once point find the probability
of getting a number lying between
2 and 6
Answers
Answered by
0
Answer:
required probability=1/2
Step-by-step explanation:
sample space={1,2,3,4,5,6} N{S}=6
let 'E' be an event getting a number between 2 and 6
so E={3,4,5}
N{E}=3
probability=N{E}/N{S}
=3/6=1/2
So the required probability is 1/2
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Answered by
0
Answer:
Probability = 0.5
Step-by-step explanation:
Total posible outcome = { 1, 2 , 3, 4, 5, 6}
Number of possible outcomes = 6
Favourable outcome = { 3, 4, 5 } ( That is no. lying btw 2 and 6 )
Number of favourable outcomes = 3
P ( F) = Number of favourable outcomes / Number of possible outcomes
P ( F) = 3 / 6
= 1/2
Probability = 0.5
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