Question

a die is thrown once,the possible outcome of getting'6' will be​

Answer 1

Solution :-

given that, a die is thrown once .

So,

→ Total outcomes = 1, 2, 3, 4, 5, 6 = Total 6

and,

→ Total favourable outcomes = getting 6 = Total 1

So,

→ Required probability = Total favourable outcomes / Total outcomes = (1/6) (Ans.)

Hence, when a die is thrown once,the possible outcome of getting '6' will be (1/6) .

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let a and b positive integers such that 90 less than a+b less than 99 and 0.9 less than a/b less than 0.91. Find ab/46

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Answer 2

Step-by-step explanation:

given that, a die is thrown once .

So, → Required probability = Total favourable outcomes / Total outcomes = (1/6) (Ans.)

Hence, when a die is thrown once,the possible outcome of getting '6' will be (1/6) .