A die is thrown once. The probability of getting an odd number on the top of the die is
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Answer:
3/6 = 1/2
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SOLUTION :
Given : A die is thrown once .
A die has 6 faces marked as 1, 2, 3, 4, 5 and 6.
If we throw one die then there possible outcomes are as follows: 1, 2, 3, 4, 5 and 6
Number of possible outcomes are = 6
Let E = Event of getting an odd number an Odd number on a die are : 1, 3, 5
Number of outcome favorable to E = 3
Probability (E) = Number of favorable outcomes / Total number of outcomes
P(E) = 3/6 = 1/2
Hence, the required probability of getting an odd number , P(E) = 1/2
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