Question

a die is thrown once what is the probability of getting
1)even number 2) odd number​

Answer 1

Answer:Total outcomes =6

Even numbers= 2,4,6

P(even)=3/6=1/2

Odd numbers=1,3,5

P(odd)=1/2

Hope It helps:

Answer 2

Answer:

TOTAL NO. OF OUTCOMES IN A DICE:- 6

1) EVEN NO. :- 2,4 AND 6 = 3

PROBABILITY OF AN EVENT:-

$\frac{favourable \: outcomes}{total \: outcomes} = \frac{3}{6}$

$= > \frac{1}{2}$

2) ODD NO. :- 1,3 AND 5 = 3

PROBABILITY OF AN EVENT=

$\frac{favourable \: outcomes}{total \: outcomes} = \frac{3}{6}$

$= > \frac{1}{2}$

so, probability of getting an even no.

$= \frac{1}{2} = 0.5$

and probability of getting an odd no.

$= \frac{1}{2} = 0.5$

VERIFY:-

$<strong><em>P</em></strong><strong><em>(</em></strong><strong><em>E_</em></strong><strong><em>1</em></strong><strong><em>)</em></strong><strong><em>+</em></strong><strong><em>P</em></strong><strong><em>(</em></strong><strong><em>E_</em></strong><strong><em>2</em></strong><strong><em>)</em></strong>$

=0.5+0.5= 1.0

HOPE IT'S HELPS YOU ❣️