Question

A die is thrown once. what is the probability of getting a number other than 4 ?​

Answer 1

Sample space = {1,2,3,4, 5,6}

n(S)=6

No. Of favourable cases ={1,2,3,5,6}

n(K) =5

So,

Probability

=n(K) /n(S)

=5/6

Answer 2

In a single throw of a die, all possible outcomes are 1, 2,3,4,5,6

Total no. of possible outcomes =6

let E be the event of getting a number other than 4.

then, the favourable outcome are 1,2,3,4,5,6.

No. of favourable outcomes =5.

=> P(getting a number other than 4)

= P(E)= 5/6✔️✔️✔️

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