A die is thrown once. What is the probability of getting an even prime number?
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A die has 6 faces marked as 1, 2, 3, 4, 5 and 6.
If we throw one die then there possible outcomes are as follows:
Possible outcomes are 1, 2, 3, 4, 5 and 6 = (6).
SOLUTION:.
Total number of outcomes= 6
Even prime number= 2
Total number of favourable outcomes= 1
Probability = Number of favourable outcomes/ Total number of outcomes.
Required probability = P(Even prime number) = 1/6
Hence, the probability of getting a Even prime number is 1/6.
HOPE THIS WILL HELP YOU...
If we throw one die then there possible outcomes are as follows:
Possible outcomes are 1, 2, 3, 4, 5 and 6 = (6).
SOLUTION:.
Total number of outcomes= 6
Even prime number= 2
Total number of favourable outcomes= 1
Probability = Number of favourable outcomes/ Total number of outcomes.
Required probability = P(Even prime number) = 1/6
Hence, the probability of getting a Even prime number is 1/6.
HOPE THIS WILL HELP YOU...
priti63:
this is wrong
how
their are 3 even outcomes and total is 6 then 3/6=1/3
it is the correct answer
read the question carefully
ok
i was wrong
thanks
Answered by
3
There are six faces in a dice.That are:1,2,3,4,5,6
In which three(2,4,6) are even numbers.So the probability of getting even numbers=favourable outcome/total no. of outcomes=3/6=1/2
Please mark me as brainliest
In which three(2,4,6) are even numbers.So the probability of getting even numbers=favourable outcome/total no. of outcomes=3/6=1/2
Please mark me as brainliest
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