Question

A die is thrown once,what is the probability of getting odd prime

Answer 1

$\sf\huge{\underline{Answer}}$

$\sf\bold{\underline{\mathbb{Question}}}$!!???

$<b><h>A die is thrown once. What is the probability of getting odd prime!?$

▶ Throwing dice for once, has a possible outcomes as..

S ={1,2,3,4,5,6}

hence,

N(S)= 6.

according to the question.!!

Outcomes , getting as odd prime.

there are total 3 prime no in sample space, those are 2,3,5 , but we need odd prime no!!

those are..

(E)={3,5}

=>N(E)= 2

we define probability as the ratio of no of possible events to the total no of outcomes!!

hence.

P(E)= $\frac{N(E)}{N(S)}$

substituting..!

P(E) = $\frac{2}{6}$

P(E) = $\frac{1}{3}$..

Therefore!!, probability of getting odd no on throwing a dice for once is $\frac{1}{3}$...