Math, asked by anahitaMahajan, 10 months ago

A die is thrown once. What is the probability of

(i) a number multiple of 2 and 3 (ii) a number 5 or 6

(iii) a number greater than and equal to 0 (iv) an odd and composite number
please explain the method for this question​

Answers

Answered by DeepthiRaj
1

Answer:

1)3 and 2

2)6

3)6 (1 2 3 4 5 6)

4)odd is 3

Answered by snigdhanayak774
0

Step-by-step explanation:

Prime numbers on a die are 2,3 and 5

So, P(getting a prime number) = 3/6 = 1/2

Using a fair six-sided die, there are 6 numbers- 1, 2, 3, 4, 5, and 6- each with an equal probability to come up when the die is rolled/tossed. This means that the probability of getting each number is exactly 1/6.

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