A die is thrown once. What is the probability that it shows a number greater than 4?
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Answered by
4
probability that it will show the number greater than 4 :- 2/6 = 1/3 ....
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Answered by
6
Total number of outcomes = 6
Number of possible outcomes = 2
Let P(A) be the probability of getting a number greater than 4
![P(A) = \frac{2}{6} \\ \\ = \frac{1}{3} P(A) = \frac{2}{6} \\ \\ = \frac{1}{3}](https://tex.z-dn.net/?f=P%28A%29+%3D++%5Cfrac%7B2%7D%7B6%7D+%5C%5C++%5C%5C++%3D++%5Cfrac%7B1%7D%7B3%7D+)
![\huge{answer \: = \frac{1}{3} } \huge{answer \: = \frac{1}{3} }](https://tex.z-dn.net/?f=+%5Chuge%7Banswer+%5C%3A++%3D++%5Cfrac%7B1%7D%7B3%7D+%7D+)
Number of possible outcomes = 2
Let P(A) be the probability of getting a number greater than 4
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