Question

a die is thrown once .what is the probablity of getting a number other than 4​

Answer 1

Answer:

So,total elements in sample space=6

Now favourable sample space(numbers other than 4):{1,2,3,5,6}

So,no of favourable elements=5

Required probability= 5/6

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Answer 2

Answer:

Hence, the required probability of getting a number greater than 4, P(E) = 1/3

Explanation:

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