Question

A die is thrown three times. Events A and B are defined as below :
A : 4 on the third throw
B : 6 on the first and 5 on the second throw
Find the probability of A given that B has already occurred
Urgent......

Answer 1

a probability =4/3
b probability=6/3=2
c probability=5/3

Answer 2

Answer:

Step-by-step explanation:

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Probability that first throw is 4 given that sum is 15

= P(first throw = 4, sum = 15)/ P(Sum = 15)

=[1/6×2×1/36]/10/216

=2/10=1/5.

Probability that sum is 15 given that first throw is 4

= P(first throw = 4, sum = 15)/ P(First throw is 4)

=[1/6×2×1/36]/1/6

=2/36=1/18