Question

A die is thrown three times, if the first throw results in 4, then find the probability of getting 15 as a sum.

Answer 1

The probability of getting 15 as a sum is $\frac{1}{108}$

Step-by-step explanation:

Formula of total outcomes of rolling a dice n times = $6^n$

So, Total outcomes of rolling 3 dice =$6^3 = 216$

We are given that the first throw results in 4

We are supposed to find  the probability of getting 15 as a sum.

So, Favorable outcomes : {(4,5,6);(4,6,5) }=2

Probability of getting 15 as a sum =$\frac{\text{Favorable outcomes}}{\text{Total outcomes}}$

Probability of getting 15 as a sum =$\frac{2}{216}=\frac{1}{108}$

Hence  the probability of getting 15 as a sum is $\frac{1}{108}$

#Learn more :

A die is thrown. Find the probability of getting a no. less than three on the die.

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Answer 2

Answer:

Step-by-step explanation:

The probability of getting 15 as a sum is

Step-by-step explanation:

Formula of total outcomes of rolling a dice n times =

So, Total outcomes of rolling 3 dice =

We are given that the first throw results in 4

We are supposed to find the probability of getting 15 as a sum.

So, Favorable outcomes : {(4,5,6);(4,6,5) }=2

Probability of getting 15 as a sum =

Probability of getting 15 as a sum =

Hence the probability of getting 15 as a sum is