Question

a die is thrown twice.find the probability 5 may not come either time
answer it soon and i will mark u brainliest

Answer 1

Answer:

25/36

Step-by-step explanation:

Given that a die is thrown twice.

Total number of outcomes n(S) = 6 * 6 = 36.

Let A be the event that 5 may not come either time.

n(A) = {5,1},{5,2},{5,3},{5,4},{5,5},{5,6},{1,5},{2,5},{3,5},{4,5},{6,5}

      = 11

P(will not come up either time) = (36 - 11)/36

                                                   = 25/36.

Hope it helps!