A die is thrown twice.Find the probability of getting a total of 9
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if a dice is thrown twice, number of outcomes = 6*6 = 36
we will get sum=9 if we get (5,4), (6,3), (4,5) (3,6)
favourable outcomes = 4
probability = 4/36 = 1/9
we will get sum=9 if we get (5,4), (6,3), (4,5) (3,6)
favourable outcomes = 4
probability = 4/36 = 1/9
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