Question

a die is thrown twice find the probability of getting an event of sum of the numbers shown is greater than 10

Answer 1

So, the total probability of getting a sum greater than 8 is:

(1/6 x 1/6) + (1/6 x 1/6)…. 10 times. This equals to: 10 x (1/36) :

P = 10/36 = 5/18

Answer 2

n(s)=36

A{(5,6),(6,6),(6,5)}

therefore P(A)=n(A)/n(S)
P(A)=3/36
P(A)=1/12