Question

A die is thrown twice , find the probability that 2 does not come up either of the times

Answer 1

ask your teacher so he or she will explain better then us

Answer 2

Answer:

11/ 36 is the Probability of the 2 not coming up either of the 2 times

Step-by-step explanation:

S = (1,1 ; 1,2 ; ............6,5 ; 6,6)

n(s) = 36  

Let the Event of the 2 not coming be A

A = (1,2 ; 2,1 ; 2,2 ; 2,3 ; 2,4 ; 2,5 ; 2,6 ; 3,2 ; 4,2 ; 5,2 ; 6,2)

n(a) = 11

Therefore , p(a) = n(a)/n(s)

                           = 11/36