A die is thrown twice .the probability that atleast one of the two throws comes up with the number 3 is
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Answered by
0
possible events
1,3
2,3
3,3
4,3
5,3
6,3
total possible outcome = 6x6= 36
probability=6/36=1/6=0.16
1,3
2,3
3,3
4,3
5,3
6,3
total possible outcome = 6x6= 36
probability=6/36=1/6=0.16
tejasri2:
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Answered by
2
sample space =
1,3
2,3
3,3
4,3
5,3
6,3
3,1
3,2
3,4
3,5
3,6
favourable events = 11
possible events = 6² = 36
probability = 11/36
Hope it helps u
1,3
2,3
3,3
4,3
5,3
6,3
3,1
3,2
3,4
3,5
3,6
favourable events = 11
possible events = 6² = 36
probability = 11/36
Hope it helps u
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