Question

a die is thrown twice. what is the probability of not getting 5 on either time and what is the probability of getting 5 exactly one time. please answer fast in need

Answer 1

Answer: Throwing a die twice and throwing two dice simultaneously are treated as the same experiment.

Sample space ={(1,1),(1,2),(1,3),(1,4),(1,5),(1,6)

                            (2,1),(2,2),(2,3),(2,4),(2,5),(2,6)

                            (3,1),(3,2),(3,3),(3,4),(3,5),(3,6)

                            (4,1),(4,2),(4,3),(4,4),(4,5),(4,6)

                            (5,1),(5,2),(5,3),(5,4),(5,5),(5,6)

                            (6,1),(6,2),(6,3),(6,4),(6,5),(6,6)}

i) P(5 will not come up either time)= Number of times 5 does not show divided by total number of outcomes

P(5 will not come up either time)=   25/36

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ii) P(5 will come up at least once)= Number of times 5 shows up at least once divided by total number of outcomes

P(5 will come up at least once)=  11/36

Answer 2

Answer:

total possible outcomes=36

P(not getting 5 either time)=34/36=17/18

P(getting 5 exactly one time)=1/36