A die is thrown twice what is the probability that 5 will come up either time and 5 will come up at least once
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So here is the answer
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The total number of outcome = 6 × 6 = 36
Method 1:
Consider the following events.
A = 5 comes in the first throw,
B = 5 comes in second throw
P(A) = 6/36,
P(B) = 6/36 and
P(not B) = 5/6
So, P(notA) = 1 – 6/36 = 5/6
∴ The required probability = 5/6 × 5/6 = 25/36
Method 2:
Let E be the event in which 5 does not come up either time.
So, the favourable outcomes are [36 – (5 + 6)] = 25
∴ P(E) = 25/36
• Number of events when 5 comes at least once = 11 (5 + 6)
∴ The required probability = 11/36
Hope It's Helpful.....:)
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