A die is thrown twice. What is the probability that 5 will notcome upeither
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2
total number of outcomes =36and 5willnot come up=11so 36-11=25 probability=25/36
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5
let be the total no of outcomes be n(s)
n(s): (1,1) (2,1) (3,1) (4,1) (5,1) (6,1)
(1,2) (2,2) (3,2) (4,2) (5,2) (6,2)
(1,3) (2,3) (3,3) (4,3) (5,3) (6,3)
(1,4) (2,4) (3,4) (4,4) (5,4) (6,4)
(1,5) (2,5) (3,5) (4,5) (5,5) (6,5)
(1,6) (2,6) (3,6) (4,6) (5,6) (6,6) = 36
the probability that 5 will not come up either = (5,1) (5,2) (5,3) (5,4) (1,5) (2,5) (3,5) (4,5) (5,5) (6,5) (6,5) =11
= 36-11=25
= 25/36
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