Question

a die is thrown twice. what is the
probability that--
i) 4 will not come up either times
ii)4 will come up at least
once?​

Answer 1

Answer:

1. 2/12

2. 1/12

Step-by-step explanation:

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Answer 2

Total no. of outcomes = 12

$\huge{\green{\bf{\underlined{Formula :- }}}}$

${\boxed{{Probability}=\frac{Total \: possible \: outcomes}{Total \: outcomes}}}$

(i) Probability (4 will not come up either times) = $\frac{10}{12} => \frac{5}{6}$

(ii) Probability (4 will come up at least once) = $\frac{2}{12} =>\frac{1}{6}$