Question

A die is thrown twice. What is the probability that sum of two numbers appearing on the top of the dice is 1st 8 2nd an identical number 3rd less than 12

Answer 1

Answer:

DICE is thrown twice. total possibilities= 36

we want at least one 5 i.e we can have one of the dice showing 5 or both dice showing 5.

both dice showing - there is only one way i.e.(5,5)

let first die shows 5 then the second die can take 1 or 2 or 3 or 4 or 6 in five ways

namely (5,1) (5,2) (5,3) (5,4) (5,6)

now suppose second die shows 5 then the first die can take 1 or 2 or 3 or 4 or 6 in five ways namely (1,5) (2,5) (3,5) (4,5) (6,5)

so total desired possibility is 1+5+5=11

so prob is 11/36