Question

a die is thrown twice what is the probability that sum will less than 6

Answer 1

Step-by-step explanation:

Let S be an event of throwing dice twice.

Number of total outcomes, n(S)=36

Let E be an event of getting dum less than 6.

E={(1,1) (1,2) (1,3) (1,4) (2,1) (2,2) (2,3) (3,1) (3,2) (4,1))

Number of favourite outcomes , n(E)=10

probability of event S, P(S)= n(E)/n(S)=10/36=0.27.

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Answer 2

Answer:

answer attached in photo