a die is thrown.what is the probabaility of getting a multiple of 3
amrit98:
1st of all a dice is thrown..na ki die is
ans is 1/3
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4
probability of getting multiple of 3= 2/6=1/3
because total no.=6
and, multiple of 3 = 3 and 6
Hope it is correct and helpful...
because total no.=6
and, multiple of 3 = 3 and 6
Hope it is correct and helpful...
Answered by
2
Tge multiples from 1 to 6 are 3 and 6 that means 2
Let E be the event 'getting a multiple of three'
P(E) = favourable outcomes / total outcomes
= 2/6
reducing by 2
=> 1/3
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