Question

A die is thrown . what is the probability. I) of getting 3? ii) of getting 7​

Answer 1

Answer:

1. Total number of outcome = 6

Number of favourable outcome = 1

$probability \: of \: getting \: 3 = \frac{1}{6}$

2. Total number of outcome = 6

Number of favourable outcome = 0

$probability \: of \: getting \: 7 = \frac{0}{6} \\ \\ = 0$

Answer 2

Answer:

i) 1/6 ii) 0

Step-by-step explanation:

Total possible chances is 6

i) Getting number 3 is once

p(3)=probability of getting 3/total chances

=1/6

ii)

Chance to get 7 is 0

p(7)=0/6=0