Question

A die is thrown. What is the probability of getting an odd number?​

Answer 1

Answer:

Hence, the required probability of getting an odd number , P(E) = 1/2

Answer 2

$hello \: mate$

SOLUTION :

Given : A die is thrown once.

➣A die has 6 faces marked as 1, 2, 3, 4, 5 and 6.

If we throw one die then there possible outcomes are as follows: 1, 2, 3, 4, 5 and 6

➣Number of possible outcomes are = 6

➣Let E = Event of getting an odd number an Odd number on a die are : 1, 3, 5  

➣Number of outcome favourable to E = 3

➣Probability (E) = Number of favourable outcomes / Total number of outcomes

➣P(E) = 3/6  = 1/2

➣Hence, the required probability of getting an odd number , P(E) = 1/2

Answer : 1/2

______________________________________

Related information :

Question : When a dice is thrown once then the probability of getting an odd number between 1 and 3 is?

➣ Answer: Possible oucomes=6, (1, 2, 3, 4, 5, 6).

Even numbers = 3, (2, 4, 6).

Probability = 3/6 or 1/2 = 50%.

Question : What is the probability of getting an even number when a dice is thrown?

➣Answer : Hence Probability of any one outcome occurring= 1/6. The event that we get that an even number on tossing the die can occur in 3 possible ways.

______________________________________

For more information visit Brainly website (brainly.in).

I hope my answer helps you....✌