Math, asked by sangamkoirala2003, 4 months ago

A die is tossed 4 times. Find the probability of getting an odd number at least once.​

Answers

Answered by Mrpagal99
1

Probability = 108/6^4

= 108/6*216 = 1/12.

Answered by linap33
2

Step-by-step explanation:

probability of getting even number =4/6=2/3

thus

the probability of getting 4 number =2/3*2/3*2/3=8/27

the probability of getting an odd number at least once =1-P(EEE)

=1-8/27

=1/12

Similar questions