A die is tossed 4 times.find the probability that 5 or 6 appear at least once. Anwser very clearly .It is for my exam.i will mark brainliest
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Answer:
65 / 81
Step-by-step explanation:
P(5 or 6 appears at least once)
= 1 - P(neither 5 nor 6 ever appears)
= 1 - P(getting 1, 2, 3 or 4 in each of the 4 tosses)
= 1 - P(getting 1, 2, 3 or 4 in a toss)⁴
= 1 - (4/6)⁴
= 1 - (2/3)⁴
= 1 - 2⁴/3⁴
= 1 - 16 / 81
= ( 81 - 16 ) / 81
= 65 / 81
AlishKoiz:
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