Question

A die is tossed 4 times.find the probability that 5 or 6 appear at least once. Anwser very clearly .It is for my exam.i will mark brainliest​

Answer 1

Answer:

65 / 81

Step-by-step explanation:

P(5 or 6 appears at least once)

= 1 - P(neither 5 nor 6 ever appears)

= 1 - P(getting 1, 2, 3 or 4 in each of the 4 tosses)

= 1 - P(getting 1, 2, 3 or 4 in a toss)⁴

= 1 - (4/6)⁴

= 1 - (2/3)⁴

= 1 - 2⁴/3⁴

= 1 - 16 / 81

= ( 81 - 16 ) / 81

= 65 / 81