Question

A die is tossed once. Find the probability of getting 3.​

Answer 1

Given,

Tossing of dice once.

To find,

The probability of getting 3.

Solution,

We know, that probability is defined as the number of favorable outcomes divided by the total number of outcomes.

P = (Number of favorable outcomes) /Total number of outcomes

Here,

Number of favorable outcomes = 1 (which is 3)

Total number of outcomes = 6 (which is 1, 2, 3, 4, 5, 6)

Now,

P( getting 3) = 1/6

Hence, probability of getting 3 = 1/6 or 0.167

Answer 2

Concept:

The area of mathematics known as probability deals with numerical representations of the likelihood that an event will occur or that a statement is true. An event's probability is a number between 0 and 1, where, roughly speaking, 0 denotes the event's impossibility and 1 denotes certainty. It is more likely that an event will occur if its probability is higher.

Given information:

A die is tossed once.

To find:

Find the probability of getting 3 after tossing the dice once.

Solution:

Probability = Number of favourable events / Total number of events

Total number of events = $6$

Number of favourable events = $1$ (as $3$ can occur once when dice is thrown)

Probability = $\frac{1}{6}$

Hence, the probability of getting $3$ after tossing the dice once is $\frac{1}{6}$.

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