Question

A die is tossed once. Find the probability of getting

(a) A number greater than 1
(b) A number 4​

Answer 1

Answer:

answer is

Step-by-step explanation:

a) Let's consider the sample space:{1,2,3,4,5,6}

So,total elements in sample space=6

Now favourable sample space(numbers other than 4):{1,2,3,5,6}

So,no of favourable elements=5

Required probability= 5/6

Hope it helps :)

Answer 2

Step-by-step explanation:

(a) Favorable outcome=2,3,4,5,6

Total outcome=1,2,3,4,5,6

Probability=5/6

=0.83

(b) Favorable outcome=4

Total outcome=1,2,3,4,5,6

Probability=1/6

=0.16