a die is tossed once. find the probability of getting :
i ) a number less than 3
ii) a prime number
iii) number greater than 2
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Heya!
lts great pleasure to help you with this question:-))
We know Empirical probability= No.of occurance/Totatal no.of events.
_____________________________
We know that a dice has six faces.So total number of events in all cases =6
1)Numers less than 3 in a dice:1,2(2 numbers)
Thus probability =
2/6=1/3
_____
_____
2)prime numbers from 1-6 are 2,3,5(3 numbers)
thus probability=
3/6=1/2
______
______
3)numbers greater than 2 till 6 are 3,4,5,6(total 4 numbers)
Thus probability =
4/6=2/3
______
______
HOPE IT HELPS
lts great pleasure to help you with this question:-))
We know Empirical probability= No.of occurance/Totatal no.of events.
_____________________________
We know that a dice has six faces.So total number of events in all cases =6
1)Numers less than 3 in a dice:1,2(2 numbers)
Thus probability =
2/6=1/3
_____
_____
2)prime numbers from 1-6 are 2,3,5(3 numbers)
thus probability=
3/6=1/2
______
______
3)numbers greater than 2 till 6 are 3,4,5,6(total 4 numbers)
Thus probability =
4/6=2/3
______
______
HOPE IT HELPS
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