A die is tossed once. Find the probability of getting: (i) a number greater than 5 (ii) an even number (iii) a prime number (iv) a number less than 1
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Answer:
S={1,2,3,4,5,6}
n(s)=6
I) A={6}
P(A)= n(A)/ n(s)
=1/6
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Throwing a dice once we’ll get (1,2,3,4,5,6)
I) the probability of getting a number greater than 5 would be 1/6 as it’s only one number
ii) 3/6 or 1/3
iii) 3/6 or 1/3
iv) 0/6, there’s no smaller number than 1
I) the probability of getting a number greater than 5 would be 1/6 as it’s only one number
ii) 3/6 or 1/3
iii) 3/6 or 1/3
iv) 0/6, there’s no smaller number than 1
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