a die is tossed once.Waht is the probability of getting head ? (i) the number 4? (ii) an odd number?
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Answer:
Step-by-step explanation:
(i)no. on a die is 1,2,3,4,5,6
number 4 = 1 (only 1 no.4)
P = no of 4's/total numbers
P =1/6
(ii)since no. on a die is 1,2,3,4,5,6
and odd no. are 1,3,5
odd numbers =3
therefore probability will be:-
P =no of odd numbers/total numbers
P = 3/6
P = 1/2
i hope this helps
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