Question

A die is tossed twice the probability of having a number greater than 4 on each toss is

Answer 1

Answer:

1/3

Step-by-step explanation:

the occurence in the toss of die is:

(1,1),(1,2),(1,3),(1,4),(1,5),(1,6),(2,1),(2,2),(2,3),(2,4),(2,5),(2,6) similarly there are 36 outcomes.

hence probability of having a number greater than 4 is 1/3

Answer 2

hey mate♥♥♥♥

here is the answer♥♥♥♥

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Answer:

p(E) = 5/9

Step-by-step explanation:

Experiment : A die is rolled twice.

no. of total possible outcomes= 36

Event : getting a number greater than 4 on each die

no. of favourable outcomes = 20

          no. of favouable outcomes for the event

p(E) = -------------------------------------------------------------

           no. of total possible outcomes

p(E) = 20/36

       = 5/9          

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