A die is tossed until 6 appears. Find the probability that it must be cast more than 5 times
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Answer. P(5th) = 5/6 * 5/6 * 5/6 * 5/6 * 1/6. P(More than 5 times) = 1 - 1/6{(1 - (5/6)^5)/(1 - 5/6)} [Sum of n terms of a GP series.] Hence the required probability is (5/6)^5.
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