Question

A die thrown is twice. The probability of getting the sum of numbers on both the dies is greater than 10 will be :

plz answer it its very important

Answer 1

Possible outcomes = (1, 1) (1, 2), (1, 3),(1, 4 ),(1, 5),(1, 6 ),(2, 1 ),(2 , 2 ),(2, 3 ),(2, 4 ),(2, 5 ),(2, 6), (3, 1 ),(3, 2 ),(3, 3 ),(3, 4 ),(3, 5 ),(3, 6),(4, 1 ),(4, 2 ),(4, 3),(4, 4 ),(4, 5 ),(4, 6 ), (5, 1 ),(5, 2 ),(5, 3),(5, 4 ),(5, 5),(5, 6 ),(6, 1 ),(6, 2 ),(6, 3 ),(6, 4 ),(6, 5 ),(6, 6 ) = 36

Favourable outcomes = (5,6), (6,5), (6,6) = 3

Probability = 3/36 = 1/12

Answer 2

Answer:

Step-by-step explanation:

For a sum > 10, possibilities are

<6,5>, <5,6>,<6,6>

Since a die is thrown twice => 6 *6 = 36 elements in sample space.

Only 3 of them gives a sum of greater than 10

Therefore probability = 3/36