Question

A die thrown once find probability
of getting (a prime number
b) number between 2 and 6 3). odd
numbel​

Answer 1

Answer:

a) 3/6 =1/2 b) 3/6=1/2.

explanation:

a)

let A be the event of getting PRIME NUMBER =(2,3,5)

A=3

N(S)=6

p(A)=n(a)/n(s)=3/6= 1/2

b)

let B be the event of getting NUMBER BETWEEN 2 and 6=(3,4,5)

B=3. n(s)=6

P(B)=n(b)/n(s)=3/6=1/2