Question

A die thrown once. What is the probability of getting a number lying between 2 and 6?

Answer 1

SOLUTION :  

Given : A die is thrown once .

A die has 6 faces marked as 1, 2, 3, 4, 5 and 6.

If we throw one die then there possible outcomes are as follows: 1, 2, 3, 4, 5 and 6

Number of possible outcomes are = 6

Let E = Event of getting a number lying between 2 & 6  

Number lying between 2 & 6  are :  3, 4, 5  

Number of outcome favourable to E = 3

Probability (E) = Number of favourable outcomes / Total number of outcomes

P(E) = 3/6  = 1/2

Hence, the required probability of getting a  number lying between 2 & 6  , P(E) = 1/2

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Answer 2

Total faces of dice=6 (total elementary events)

Numbers between 2 to 6=3,4,5

Total=3

So, probability=favourable elementary events/total elementary events

=3/6

=1/2