Question

A die was thrown 6 times such that all the 6 outcomes were distinct if x denotes the mean and y denotes the median of all the outcomes, then the value of x-y upon x+y is
(1) 7
(2) 0
(3) 3.5
(4) 1

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Answer 1

When a die is thrown the possible outcomes are ( 1,2,3,4,5,6)
So when a die is thrown 6 times and all the outcomes are distinct we can consider the outcome (1,2,3,4,5,6)
Now mean x=(1+2+3+4+5+6)/6
= 21/6

Now it’s median = (3+4)/2
= 7/2
Now x-y/x+y
X-Y= 21/6-7/2
=21-14/6.
=7/6
X+Y= 21/6+7/2
= (21+14)/6
=35/6
= 5
X-Y/X+Y=7/6/5
= 7/30