a dieis thrown once. find the probability of getting a number more than 3.
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Sample space ={1,2,3,4 5,6}
N(e)=1
S(e)=6
P(e)jN(e)/S(e)=1/6
N(e)=1
S(e)=6
P(e)jN(e)/S(e)=1/6
Answered by
0
When a dice is thrown, the Outcomes are 1,2,3,4,5 and 6....
Favourable Outcomes are 4,5 and 6
No. Of Favourable Outcomes = 3
Probability = No. Of Favourable Outcomes / Total no. Of Outcomes
= 3/6
= 1/2
Favourable Outcomes are 4,5 and 6
No. Of Favourable Outcomes = 3
Probability = No. Of Favourable Outcomes / Total no. Of Outcomes
= 3/6
= 1/2
gaurav2013c:
brainliest it if helped....
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