Question

A dielectric material of dielectric constant k is inserted in half portion between the plates of a parallel plate capacitor. if its initial capacitance is c, what is the new capacitance?

Answer 1

Capacitance between the parallel plates of the capacitor, C = 8 pF
Initially, distance between the parallel plates was d and it was filled with air. Dielectric constant of air, k = 1
Capacitance, C, is given by the formula,

Where, A = Area of each plate

= Permittivity of free space
If distance between the plates is reduced to half, then new distance, d' = d / 2
Dielectric constant of the substance filled in between the plates,

= 6
Hence, capacitance of the capacitor becomes

Taking ratios of equations (i) and (ii), we obtain

Therefore, the capacitance between the plates is 96 pF.
Previous QuestionNext Question

Answer 2

Bring a rectangular slab made up of conducting material between the plates of the capacitor. The thickness of the slab must be less than ...