Question

A dielectric medium is placed in an electric field E0. The field induced inside the medium.

Answer 1

Answer:

Relative permittivity is the ratio of permittivity of medium or permittivity of vacuum. e.g., ∈ₐ = ∈/∈₀ here ∈ₐ shows relative permittivity of the dielectric.

Relative permittivity is the ratio of permittivity of medium or permittivity of vacuum. e.g., ∈ₐ = ∈/∈₀ here ∈ₐ shows relative permittivity of the dielectric.It is also known as dielectric constant e.g., K

Relative permittivity is the ratio of permittivity of medium or permittivity of vacuum. e.g., ∈ₐ = ∈/∈₀ here ∈ₐ shows relative permittivity of the dielectric.It is also known as dielectric constant e.g., KAgain, Electric field intensity , E = Q/4π∈₀Kr² in a medium of dielectric constant is K

Relative permittivity is the ratio of permittivity of medium or permittivity of vacuum. e.g., ∈ₐ = ∈/∈₀ here ∈ₐ shows relative permittivity of the dielectric.It is also known as dielectric constant e.g., KAgain, Electric field intensity , E = Q/4π∈₀Kr² in a medium of dielectric constant is KNow, according to question,

Relative permittivity is the ratio of permittivity of medium or permittivity of vacuum. e.g., ∈ₐ = ∈/∈₀ here ∈ₐ shows relative permittivity of the dielectric.It is also known as dielectric constant e.g., KAgain, Electric field intensity , E = Q/4π∈₀Kr² in a medium of dielectric constant is KNow, according to question,Electric field intensity induced in a dielectric when placed in an external field is 1/10 times of external field.

Relative permittivity is the ratio of permittivity of medium or permittivity of vacuum. e.g., ∈ₐ = ∈/∈₀ here ∈ₐ shows relative permittivity of the dielectric.It is also known as dielectric constant e.g., KAgain, Electric field intensity , E = Q/4π∈₀Kr² in a medium of dielectric constant is KNow, according to question,Electric field intensity induced in a dielectric when placed in an external field is 1/10 times of external field.Means , Electric in dielectric = Electric field in vacuum/10

Relative permittivity is the ratio of permittivity of medium or permittivity of vacuum. e.g., ∈ₐ = ∈/∈₀ here ∈ₐ shows relative permittivity of the dielectric.It is also known as dielectric constant e.g., KAgain, Electric field intensity , E = Q/4π∈₀Kr² in a medium of dielectric constant is KNow, according to question,Electric field intensity induced in a dielectric when placed in an external field is 1/10 times of external field.Means , Electric in dielectric = Electric field in vacuum/10Q/4π∈₀Kr² = Q/4π∈₀r²10

Relative permittivity is the ratio of permittivity of medium or permittivity of vacuum. e.g., ∈ₐ = ∈/∈₀ here ∈ₐ shows relative permittivity of the dielectric.It is also known as dielectric constant e.g., KAgain, Electric field intensity , E = Q/4π∈₀Kr² in a medium of dielectric constant is KNow, according to question,Electric field intensity induced in a dielectric when placed in an external field is 1/10 times of external field.Means , Electric in dielectric = Electric field in vacuum/10Q/4π∈₀Kr² = Q/4π∈₀r²10K = 10

Relative permittivity is the ratio of permittivity of medium or permittivity of vacuum. e.g., ∈ₐ = ∈/∈₀ here ∈ₐ shows relative permittivity of the dielectric.It is also known as dielectric constant e.g., KAgain, Electric field intensity , E = Q/4π∈₀Kr² in a medium of dielectric constant is KNow, according to question,Electric field intensity induced in a dielectric when placed in an external field is 1/10 times of external field.Means , Electric in dielectric = Electric field in vacuum/10Q/4π∈₀Kr² = Q/4π∈₀r²10K = 10Hence, relative permittivity of dielectric is 10

Explanation:

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