Physics, asked by narendranrv004, 1 day ago

A dielectric slab of constant k is inserted between plates of capacitor after disconnecting from the battery, then:
(I) New charge on capacitor
(II) New value of Electric Field
(III) New value of Potential difference

Answers

Answered by oODivineGirlOo

0

Answer:

(I) New charge on capacitor✔

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