Physics, asked by babul547, 7 months ago

A dielectric slab of dielectric constant KK is placed between the plates of a parallel plate capacitor carrying charge qq. The induced charge q^{\prime}q ′
on the surface of slab is given by

Answers

Answered by charanjeetNatt
2

q' = q(1 - 1/K)

because of dielectric polarization, positive charges are displaced in the direction of the field and negative charges shift in the opposite direction. This creates an internal electric field that reduces the overall field within the dielectric itself.

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