a dies is thrown for once what is the probability of getting an even nunber nd a number greater than2
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Answered by
1
Step-by-step explanation:
Throwing of a die can have 6 possible outputs.
1, 2, 3, 4, 5 and 6.
So, N(S) (number of Space) is 6
The numbers having greater value than 2 are- 3, 4, 5 and 6.
So, we can get a number which is greater than 2 in four ways.
So, N(E) (number of Events) is 4
If probability of finding a number greater than 4 in throw of a die is denoted by P(A) , then-
P(A)=N(E)N(S)=46=23 (a)
There you go!
Answered by
0
Answer:
There are 6 number on a dice - 1, 2, 3, 4, 5 and 6
Numbers more than 2 - 4 numbers
Probability- 4/6
Hope this helps you :)
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