A dies is thrown.Onces find the probability of get ting a number which lies between 2 and6
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total possible cases = 6 {1,2,3,4,5,6}
favourable cases = 3 {3,4,5}
probability of getting a number which lies between 2 and 6 = 3/6 =1/2
hope it will help you.....
Answered by
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when a dice is thrown sample space(s)=
{1,2,3, 4,5,6}
n(s)=6
let 'A' be the event that the number should be lied between 2&6
A={3,4,5}
n(A),=3
p(A)=n(A)/n(s). [formula]
p(A)=3/6=1/2
probability of getting number between 2 and 6 is 1/2
hope u will be helped
tnx
mark as brainliest plz
if it help
{1,2,3, 4,5,6}
n(s)=6
let 'A' be the event that the number should be lied between 2&6
A={3,4,5}
n(A),=3
p(A)=n(A)/n(s). [formula]
p(A)=3/6=1/2
probability of getting number between 2 and 6 is 1/2
hope u will be helped
tnx
mark as brainliest plz
if it help
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