A dies is thrown, what is the Probablity of getting:-
A) An odd prime number
B) A number greater than 7
C) An even number
What is the answer
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Answers
Step-by-step explanation:
A)There are Two odd prime numbers in a dies so total numbers are six.
Probability would be=2/6
B) In a dies there is no greater number than 6 so the probability would be=0/6
C) In a dies there are three even numbers so the probability=3/6
Tip:If you want to decrease into smallest form you can. For e.g. 2/6=1/3 & 3/6=1/2.
Answer:
A dice has 6 sides with 1,2,3,4,5 and 6 dotes
Therefore,
A) An odd prime
Ans: In 1,2,3,4,5 and 6 there are 3 prime no.s
They are 2,3,and 5.
In this 3 and 5 are odd and 2 is even.
Therefore probability of getting an odd prime is 2/6.
B)A no. greater than 7
In a dice a no. Greater than 7 is not possible as the greatest no. Of a dice is 6
Therefore the probability is 0/6.
C)An even no.
In a dice as I told above there are 6 side in which dotes are marked.
In each side 1,2,3,4,5 and 6 dotes are marked.
In the no.s 1,2,3,4,5 and 6 only thred no.s are even.
They are 2,4 and 6.
Therefore probability of getting an even no. is 3/6. Which can be further simplified into 1/2.
Hope it helps
And my language is clear.
All the best!!