a difference between the semi perimeter and the side of a triangle ABC are 8 cm 7 cm and 5 cm respectively find the area of the triangle
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Let the semiperimeter = x
Side A's difference = 8 cm
Side B's difference = 7 cm
Side C's difference = 5 cm
Side A = x+8 cm
Side B = x+7 cm
Side C = x+5 cm
Now ,
x = (x+8+x+7+x+5)/2
x = 3x+20/2
2x = 3x+20
-x = 20
x= -20
But the semiperimeter can't be in negative.
Now Area of ∆ABC :
= 74.8331477 cm² = 74.833 cm² Approximatel
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