Question

A difference in density between gases creates buoyancy, which is the ability of an object to float. At 0^\circ0 ∘ 0, degreesC, helium has a density of 0.18\text{ kg/m}^30.18 kg/m 3 0, point, 18, start text, space, k, g, slash, m, end text, cubed. At 0^\circ0 ∘ 0, degreesC, regular air has a density of 1.29\text{ kg/m}^31.29 kg/m 3 1, point, 29, start text, space, k, g, slash, m, end text, cubed. In kilograms, how much mass can a cubic meter of helium float in regular air at 0^\circ0 ∘ 0, degreesC?

Answer 1

Answer:

Ratio mass helium to air is 1 / 1.03

Step-by-step explanation:

We need to find the difference in masses of helium to normal air.

The density of helium is given as 30.18 kg/m3

The density of air is 31.29 kg/m3

The formula of density is

Density = Mass / Volume

Mass = Density x volume

Now we need to find mass for 1m3 volume of helium

Mass = 30.18 x 1

Mass = 30.18 kg

Similarly the mass of air would be = 31.29

Ratio mass helium to air is = 30.18/31.29 = 1 / 1.03