A diffraction grating contains 5000 lines per nm. If light of wavelength of 5896 Å is incident on it, find the angle of diffraction of the second maxima.
Answers
A diffraction grating contains 5000 lines per cm. [ per nm can't be possible ] If light of wavelength of 5896 Å is incident on it.
To find : The angle of diffraction of the second Maxima.
solution : here a diffraction grating contains 5000 lines per cm.
so, d = 1/N = 1/(5000) × 10¯² m
= 2 × 10¯⁶ m
wavelength of light, λ = 5896 A° = 5.896 × 10^-7 m
using formula, dsinθ = nλ
for second Maxima, n = 2
⇒(2 × 10¯⁶) sinθ = 2 × 5.986 × 10^-7
⇒sinθ = 5.896/10 = 0.5896
⇒θ = 36.13°
Therefore the angle of diffraction of the second Maxima will be 36.13°.
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